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Configuration = 115
cycles = (10 4 2 7 3)(9 6 1 8 5)

a = 4, b = 7, c = 10
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cycles = (10 3)(9 1 5 8 6)(7)(4 2)

a = 1, b = 5, c = 9
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cycles = (10 7)(9 4 2)(8 6)(5)(3)(1)

a = 7, b = 8, c = 10
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cycles = (10 6 7)(9)(8 4 2)(5)(3)(1)

a = 6, b = 7, c = 10
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cycles = (10)(9)(8)(7 4 2)(6)(5)(3)(1)